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#numactl --hardware% F. e8 N& a, n+ a6 a; E* s: h9 @
1 P& J4 P: x) f结果如下
6 }# \7 o+ ~" j7 K9 g# [0 K9 l) d. y
available: 2 nodes (0-1)8 W; N+ ^6 ~9 N o2 e* ^
node 0 cpus: 4 5 6 7 12 13 14 15" N3 b( l% F; h) B% {
node 0 size: 28663 MB
/ I& l4 i+ w3 B( G7 Xnode 0 free: 25761 MB! [7 @& M& E# F( O _
node 1 cpus: 0 1 2 3 8 9 10 11
5 N" ?% u: h7 ^; H9 U. @( ?node 1 size: 20480 MB5 P( i5 R8 i7 \' v1 g$ H0 z
node 1 free: 18917 MB
0 w# U+ y: A& h/ snode distances:$ }2 u; T0 n5 n8 ]9 v) L6 D# ? U
node 0 1 + ]3 {, P; q) {9 ^4 z
0: 10 20
# t# ]# X. ^& Q4 S* b8 L 1: 20 10
7 a3 @( E' O$ L$ Y9 J; C--------------------- 2 v$ c" ]' Z2 ^& j- O. _
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发表于 2018-12-11 15:15:13