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计算PG数：0 T% ^, g2 s1 P! k! B6 i( q8 O- \' |
6 K' `6 e3 {- v- v9 k! {9 nceph集群中的PG总数：
+ n! H9 b% u: {# G% b PG总数 = (OSD总数 * 100) / 最大副本数，结果必须舍入到最接近的2的N次方幂的值；6 v5 N( o# W: s8 a& A( }. t7 d7 V
! P6 j. `7 i/ w# ?. Jceph集群中每个pool中的PG总数：- A) ~4 H0 m5 a" \6 u6 Y! i+ X. O
存储池PG总数 = (OSD总数 * 100 / 最大副本数) / 池数2 }4 s; Q$ T+ w" C" v# p
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获取现有的PG数和PGP数值
8 @2 g9 K" P( wceph osd pool get data pg_num
1 D, h- g/ D6 h6 \' B- f" {% Uceph osd pool get data pgp_num
6 p% l! j2 O0 h; P13. 修改存储池的PG和PGP" N8 ^, ~: _* Y! H7 H! ]1 X/ K
ceph osd pool set data pg_num = 1" Q( g: D: Y4 c
ceph osd pool set data pgp_num = 1( c! K4 H& A" Y
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发表于 2021-10-9 17:00:04